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Calculus

Suppose a certain object moves in a straight line with velocity v(t)= -2+t+3sin(pi t) where v is in meters per second and t is in seconds. Determine the net change in distance of the object from time t=0 to time t=6 seconds and find the object's average velocity on this interval.

Do I just find the antiderivative and solve when t=6? Please help

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Kazuya

  1. dx/dt = -2 + t + 3 sin (pi t)
    pi t = 2 pi when t = 2 seconds
    so we are doing several periods, danger, it luckily asks for the NET distance it goes and not the distance it travels during the 6 seconds (end - begin not total including back and forth)
    so yes
    x= -2t+t^2/2-(3/pi)cos(pi t)at 6 - at 0
    danger again - remember cos 0 = 1

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    Damon

  2. oh, and cos (6 pi) = 1 as well so forget about the trig :)

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    Damon

  4. Thanks so much Damon!

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    Kazuya

  5. You are welcome.

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    Damon

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