What would be the volmeter reading of the cell of Ni and Cu
E Ni2+/Ni= -0.24V
E Cu/Cu2+= 0.34 V
E cell=E cathode - E anode= -0.24 V - (-0.34 V) =0.10V
I think this in incorrect as no answer like this is given
To determine the voltmeter reading of the cell with a nickel (Ni) and copper (Cu) half-cell, you need to apply the equation Ecell = Ecathode - Eanode.
Given that E Ni2+/Ni = -0.24 V and E Cu/Cu2+ = 0.34 V, you correctly calculated the Ecell as -0.24 V - (-0.34 V) = 0.10 V.
However, voltmeter readings usually do not display negative values. Therefore, the voltmeter reading of the cell would be 0.10 V. This indicates that the voltage across the cell is positive, indicating a spontaneous redox reaction.