The length, breadth and height of a cuboidal box are 2m10cm, 1m and 80cm respectively. Find the are of canvas required to cover this box.
To find the area of canvas required to cover the box, we need to calculate the surface area of the box.
The surface area of a cuboid is given by the formula:
Surface Area = 2(lw + lh + wh)
Given:
Length = 2 m 10 cm = 2.10 m
Breadth = 1 m
Height = 80 cm = 0.80 m
Substituting the values into the formula, we get:
Surface Area = 2(2.10 * 1 + 2.10 * 0.80 + 1 * 0.80)
Simplifying the equation, we have:
Surface Area = 2(2.10 + 1.68 + 0.80)
Surface Area = 2(4.58)
Surface Area = 9.16 m²
Therefore, the area of canvas required to cover the box is 9.16 square meters.
To find the surface area of the cuboidal box, we need to calculate the area of each of its six faces.
Given:
Length = 2m 10cm = 2m + 10cm = 2m + 0.1m = 2.1m
Breadth = 1m
Height = 80cm = 80cm ÷ 100cm = 0.8m
Now, we can find the area of each face:
1. Top and bottom faces: Area = Length × Breadth = 2.1m × 1m
2. Front and back faces: Area = Length × Height = 2.1m × 0.8m
3. Left and right faces: Area = Breadth × Height = 1m × 0.8m
To calculate the total area of the canvas required to cover the box, we need to add the areas of all six faces:
Total Area = 2 × (Top and bottom faces) + 2 × (Front and back faces) + 2 × (Left and right faces)
Now, let's substitute the values and calculate the surface area:
Total Area = 2 × (2.1m × 1m) + 2 × (2.1m × 0.8m) + 2 × (1m × 0.8m)
Simplifying the calculation:
Total Area = 2 × 2.1m × 1m + 2 × 2.1m × 0.8m + 2 × 1m × 0.8m
Total Area = 4.2m² + 3.36m² + 1.6m²
Total Area = 9.16m²
Therefore, the area of canvas required to cover this box is 9.16 square meters.
there are six faces on the box.
two of length x breadth
two of length x height
two of breadth x height
so, just use your dimensions and crank out the products.