Forces F1=7.50N and F2=5.30N are applied tangentially to a wheel with radius 0.330 m. What is the net torque on the wheel due to these two forces for an axis perpendicular to the wheel and passing through its center?

It depends upon whether or not the forces F1 and F2 are both in the same rotational direction. It they are, add the torques. If not, subtract one from the other. For a tangential force, torque = (force)x(radius)

Let's consider two cases:

Case 1: Forces F1 and F2 are applied in the same rotational direction.
In this case, the net torque will be the sum of the individual torques due to F1 and F2.
Torque1 = F1 x radius = 7.50 N x 0.330 m = 2.475 Nm
Torque2 = F2 x radius = 5.30 N x 0.330 m = 1.749 Nm
Net Torque = Torque1 + Torque2 = 2.475 Nm + 1.749 Nm = 4.224 Nm

Case 2: Forces F1 and F2 are applied in opposite rotational directions.
In this case, the net torque will be the difference between the individual torques due to F1 and F2.
Net Torque = Torque1 - Torque2 = 2.475 Nm - 1.749 Nm = 0.726 Nm

So, the net torque on the wheel depends on whether the forces are applied in the same rotational direction or not. If they are, the net torque is 4.224 Nm, and if they aren't, the net torque is 0.726 Nm.

To calculate the net torque on the wheel, we first need to determine the torque created by each force. The formula for torque is torque = (force) x (radius).

Given:
Force F1 = 7.50 N
Force F2 = 5.30 N
Radius of the wheel = 0.330 m

To find the torque created by each force, we multiply the force by the radius:

Torque due to F1 = F1 x radius
= 7.50 N x 0.330 m
= 2.475 Nm

Torque due to F2 = F2 x radius
= 5.30 N x 0.330 m
= 1.749 Nm

Since the forces are tangential, we need to determine the net torque by adding the absolute values of the torques if the forces are in the same rotational direction, or subtracting one from the other if they are in opposite rotational directions.

In this case, the torques due to F1 and F2 are both in the same rotational direction. Therefore, we add their absolute values to find the net torque:

Net torque = |Torque due to F1| + |Torque due to F2|
= |2.475 Nm| + |1.749 Nm|
= 2.475 Nm + 1.749 Nm
= 4.224 Nm

Hence, the net torque on the wheel due to these two forces is 4.224 Nm.

To find the net torque on the wheel, we need to consider the torques produced by each force individually and then determine whether we need to add or subtract them.

The torque produced by a force is given by the formula: Torque = Force x Radius

Given:
Force F1 = 7.50 N
Force F2 = 5.30 N
Radius of the wheel = 0.330 m

First, we calculate the torques produced by each force:
Torque due to F1 = F1 x Radius = 7.50 N x 0.330 m
Torque due to F2 = F2 x Radius = 5.30 N x 0.330 m

Next, we determine the rotational direction of the forces. Since the problem states that F1 and F2 are applied tangentially to the wheel, the rotational direction depends on whether they are both in the same direction or not.

If F1 and F2 are in the same rotational direction, we add the torques:
Net torque = Torque due to F1 + Torque due to F2

If F1 and F2 are in different rotational directions, we subtract one torque from the other:
Net torque = Torque due to F1 - Torque due to F2

So, based on the given information, you need to determine whether F1 and F2 are in the same rotational direction or not, and then use the appropriate formula to calculate the net torque on the wheel.