Differential equation

(Y'-x^2y^2)/sec x=0

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  1. since sec x is never zero, we can get rid of it. Now we have

    y' - x^2y^2 = 0
    dy/y^2 = x^2 dx
    -1/y = 1/3 x^3 + c/3
    y = -3/(x^3+c)

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