# Differential equation

(Y'-x^2y^2)/sec x=0

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1. since sec x is never zero, we can get rid of it. Now we have

y' - x^2y^2 = 0
dy/y^2 = x^2 dx
-1/y = 1/3 x^3 + c/3
y = -3/(x^3+c)

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