you have 20ml of an aqueous solution of 0.2M NaOH. if you add distilled water to this solution until you have 200ml , what will be the concentration? How many times did you dilute it?
it is diluted 10 times, so .02M. You added one part original, nine parts water.
The concentration is 0.02M then the solution is diluted 10 times by adding 180ml of distilled water
To find the final concentration after dilution, we can use the formula:
C1V1 = C2V2
Where:
C1 = Initial concentration of the solution
V1 = Initial volume of the solution
C2 = Final concentration of the solution
V2 = Final volume of the solution
In this case, we have an initial solution with a concentration of 0.2M NaOH and a volume of 20ml (C1 = 0.2M, V1 = 20ml). After dilution, the final volume becomes 200ml (V2 = 200ml), and we want to find the final concentration (C2).
First, we can rearrange the formula to solve for C2:
C2 = (C1 * V1) / V2
Substituting the values we have:
C2 = (0.2M * 20ml) / 200ml
C2 = 0.02M
Therefore, the final concentration of the solution after dilution is 0.02M NaOH.
To determine how many times the solution was diluted, we divide the initial volume (V1 = 20ml) by the final volume (V2 = 200ml):
Number of dilutions = V1 / V2
Number of dilutions = 20ml / 200ml
Number of dilutions = 0.1
Therefore, the solution was diluted by a factor of 0.1 or 1/10.