Six numbers are written in ascending order: 1.4, 3, 4.7, 5.8, a, 11. Find all possible values of a if the number 11 is considered to be an outlier.
The answers say 5.8 is less than or equal to a<6.2 but i am struggling to figure this out
To find the possible values of 'a', let's analyze the given information step by step:
1. We are given six numbers in ascending order: 1.4, 3, 4.7, 5.8, a, 11.
2. We are also told that 11 is considered an outlier.
3. An outlier is a value that significantly deviates from other values.
4. In this case, since the numbers are written in ascending order, all values before the outlier (11) will be less than 11.
5. Therefore, the value of 'a' cannot be greater than or equal to 11.
Now, let's look at the numbers that come immediately after 'a':
1. 'a' is followed by the number 11.
2. Since 11 is considered the outlier, we can conclude that 'a' must be less than 11.
3. The greatest value 'a' can take is the one that immediately precedes 11 in the ascending order sequence.
4. In this case, the number that comes right before 11 is 5.8.
5. Therefore, the possible value of 'a' should be less than or equal to 5.8.
Combining the above analysis, we can summarize the possible values of 'a' as follows:
5.8 is less than or equal to 'a' < 11.
Please note, without additional information or constraints, we cannot determine an exact value for 'a,' only a range based on the given conditions.