# Physics

The 2-cm (radius) current loop shown in the figure is changing from Î¸1 = 11 degrees to Î¸2 = 66 degrees in a magnetic field 2 T in 0.5 seconds. What is the magnitude of the induced emf to the nearest hundredth of a millivolt?

The wire in Problem 2 has a thickness of 1.04 mm and a resistivity of 1.71 x 10-8 Î©m. To the nearest tenth of a milliamp what is the induced current in the loop

Calcuate the change in magnetic flux and divide it by the time interval. That will give you the average EMF.
V = (change in BA cos theta)/0.5 s
B = 2 T
A = pi R^2 (with R in meters)
This assumes that "theta" is measured between the B field direction and the normal to the loop.

For the last part, compute the resistance of the wire
R = resisitivity* 2 pi R/A
since resisistivity is in ohm-cn, A must be in cm^2 and R in cm

I = V/R

1. 👍 0
2. 👎 0
3. 👁 153

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