Calculate the concentration (molarity) of copper(ii) sulfate, CuSO4, in 1L of solution containing 200g Copper-Sulfate-Penetahydrate(CuSO4x5H2O)?
mols CuSO4*5H2O = grams/molar mass
M CuSO4*5H2O = mols/L = ?
You have 1 mol CuSO4 in 1 mol CuSO485H2O; M CuSO4 = mols CuSO4/L solution.
To calculate the molarity of copper(II) sulfate in a 1L solution, we need to first convert the mass of the copper(II) sulfate pentahydrate to moles and then divide by the volume to get the concentration in moles per liter (M).
Step 1: Convert the mass of CuSO4·5H2O to moles.
The molar mass of CuSO4·5H2O is:
Cu: 63.55 g/mol
S: 32.07 g/mol
O(x4): 16.00 g/mol
H(x10): 1.01 g/mol
Molar mass of CuSO4·5H2O = (63.55 + 32.07 + (4 x 16.00) + (10 x 1.01)) + (5 x (2 x 1.01 + 16.00))
= 159.61 g/mol
Now, divide the given mass (200g) by the molar mass to get the moles of CuSO4·5H2O:
Moles of CuSO4·5H2O = mass / molar mass
= 200g / 159.61 g/mol
≈ 1.254 moles
Step 2: Calculate the molarity of CuSO4 in the 1L solution.
Molarity (M) = Moles / Volume (in liters)
Since we have a 1L solution, we can simply use the moles calculated in step 1:
Molarity of CuSO4 = Moles / Volume
= 1.254 moles / 1L
= 1.254 M
Therefore, the concentration (molarity) of copper(II) sulfate in a 1L solution containing 200g of copper(II) sulfate pentahydrate is 1.254 M.
To calculate the molarity of copper(ii) sulfate in the given solution, we need to determine the number of moles of copper(ii) sulfate present and then divide it by the volume of the solution.
First, we need to convert the mass of Copper-Sulfate-Pentahydrate (CuSO4·5H2O) to moles. We can do this by using the molar mass of CuSO4·5H2O.
The molar mass of CuSO4·5H2O can be calculated as follows:
Cu: 63.55 g/mol (molar mass of copper)
S: 32.07 g/mol (molar mass of sulfur)
O: 16.00 g/mol (molar mass of oxygen)
H: 1.01 g/mol (molar mass of hydrogen)
The total molar mass of CuSO4·5H2O is:
(63.55 g/mol * 1) + (32.07 g/mol * 1) + (16.00 g/mol * 4) + (1.01 g/mol * 10) = 249.71 g/mol
Next, we can calculate the number of moles of CuSO4·5H2O using its molar mass and mass given:
Number of moles = Mass / Molar mass
Number of moles = 200 g / 249.71 g/mol
Now that we know the number of moles of CuSO4·5H2O, we can calculate the molarity of copper(ii) sulfate using the formula:
Molarity = Number of moles / Volume of solution
Since the volume of the solution is given as 1L, we can directly substitute the values into the formula:
Molarity = (200 g / 249.71 g/mol) / 1 L
Molarity = 0.801 M
Therefore, the concentration (molarity) of copper(ii) sulfate in the given 1L solution is 0.801 M.