Math-college

Here is a linear inequality to solve:

8x + 8 < 3 (x + 1)

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  1. 8 x + 8 < 3 ∙ x + 3 ∙ 1

    8 x + 8 < 3 x + 3

    Subtract 8 to both sides

    8 x + 8 - 8 < 3 x + 3 - 8

    8 x < 3 x - 5

    Subtract 3 x to both sides

    8 x - 3 x < 3 x - 5 - 3 x

    5 x < - 5

    Divide both sides by 5

    5 x / 5 < - 5 / 5

    x < - 1

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