hiw much heat is needed to raise the temperature of 0.800 kg. ethyl alcohol form 15.0 celcius to its boiling point 78.3 celcius
you will need the specific heat contents, ca, for ethyl alcohol.
Heat= mass*ca*changeinTemp
=.8kg*ca*(78.3-15)
To calculate the amount of heat needed to raise the temperature of a substance, you can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q = amount of heat energy (in Joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in J/kg·°C)
ΔT = change in temperature (in °C)
First, we need to find the change in temperature (ΔT). ΔT is calculated by subtracting the initial temperature from the final temperature:
ΔT = final temperature - initial temperature
ΔT = 78.3°C - 15.0°C
ΔT = 63.3°C
Now, we can calculate the amount of heat energy (Q) using the specific heat capacity of ethyl alcohol. The specific heat capacity of ethyl alcohol is approximately 2.4 J/g·°C or 2,400 J/kg·°C. Since the mass is given in kilograms, we will use the value 2,400 J/kg·°C.
Q = 0.800 kg * 2,400 J/kg·°C * 63.3°C
Q = 121,920 Joules
Therefore, approximately 121,920 Joules of heat energy is needed to raise the temperature of 0.800 kg of ethyl alcohol from 15.0°C to its boiling point of 78.3°C.
To calculate the amount of heat required to raise the temperature of a substance, you need to use the equation:
Q = m * C * ΔT
where:
Q is the heat (in Joules),
m is the mass of the substance (in kilograms),
C is the specific heat capacity of the substance (in J/kg·°C), and
ΔT is the change in temperature (in °C).
First, let's find the value of ΔT by subtracting the initial temperature from the final temperature:
ΔT = (Final temperature) - (Initial temperature)
= 78.3°C - 15.0°C
= 63.3°C
Next, determine the specific heat capacity of ethyl alcohol. The specific heat capacity of ethyl alcohol is approximately 2.44 J/g·°C, which we need to convert to J/kg·°C since the mass is given in kilograms:
1 g = 0.001 kg
So, the specific heat capacity (C) of ethyl alcohol is:
C = 2.44 J/g·°C * (0.001 kg / 1 g)
= 2.44 J/kg·°C
Now we can calculate the heat (Q):
Q = m * C * ΔT
= 0.800 kg * 2.44 J/kg·°C * 63.3°C
≈ 123.68 Joules
Therefore, approximately 123.68 Joules of heat is needed to raise the temperature of 0.800 kg of ethyl alcohol from 15.0°C to its boiling point, 78.3°C.