Sasha finished mowing lawns at 4:15 PM. It took 1^3/4 h to mow the first lawn. The second and third lawns she mowed each took 1^1/5 h. She took one 45-min break. When did Sasha begin mowing the first lawn?

A. 10.05 A.M.
B. 11:05 A.M.
C. 11:21 A.M.
D. 12:21 P.M.
thinking the answer is C. am i correct

Assuming she only mowed the three lawns, then her total time was

1 3/4 + 2*(1 1/5) + 3/4 = 4 9/10 hours.

That's 4:54, so subtracting that from 4:15, we have a start time of (using the 24-hour clock)

16:15 - 4:54 = 15:75 - 4:54 = 11:21

You are correct. Good job.

thank you so much steve!!!!!

To find out when Sasha began mowing the first lawn, we need to calculate the total time it took for her to mow the lawns and add it to the time of her break.

The first lawn took 1^3/4 hours to mow, which is equivalent to 1 hour and 45 minutes.
The second and third lawns each took 1^1/5 hours to mow, which is equivalent to 1 hour and 12 minutes.

So, the total time Sasha spent mowing is:
1 hour and 45 minutes + 1 hour and 12 minutes + 1 hour and 12 minutes = 3 hours and 9 minutes.

She also took a 45-minute break.

Adding the mowing time and the break time, we get:
3 hours and 9 minutes + 45 minutes = 3 hours and 54 minutes.

To determine when Sasha began mowing, we subtract 3 hours and 54 minutes from 4:15 PM.

4:15 PM - 3 hours and 54 minutes = 12:21 PM.

Therefore, Sasha began mowing the first lawn at 12:21 PM.

The correct answer is D. 12:21 P.M.

To find out when Sasha began mowing the first lawn, we need to add up the time it took her to mow each lawn and the time she took for her break.

First, let's convert the mixed numbers to improper fractions for easier calculations:
1^3/4 h = (4 + 3/4) h = 7/4 h
1^1/5 h = (5 + 1/5) h = 6/5 h

Now, let's add up the times:
Total time for mowing the first lawn: 7/4 h
Total time for mowing the second lawn: 6/5 h
Total time for mowing the third lawn: 6/5 h

Additionally, Sasha took a 45-minute break, which can be represented as 45/60 h = 3/4 h.

Now, let's add up all the times:
Total time for mowing all three lawns and the break:
7/4 h + 6/5 h + 6/5 h + 3/4 h

To add these fractions, we need to find a common denominator, which is 20.

(7/4 h) x (5/5) = 35/20 h
(6/5 h) x (4/4) = 24/20 h
(6/5 h) x (4/4) = 24/20 h
(3/4 h) x (5/5) = 15/20 h

Now, let's add up the fractions:
35/20 h + 24/20 h + 24/20 h + 15/20 h = 98/20 h

To convert 98/20 h back to a mixed number:

Divide 98 by 20: 98 ÷ 20 = 4 remainder 18

So, 98/20 h is equal to 4 + 18/20 h.

Now, since Sasha began mowing at 4:15 PM, we need to subtract the total time from 4:15 PM to find out the starting time.

4:15 PM - 4 hours (since 4 hours is equal to 60 minutes) = 12:15 PM

Therefore, Sasha started mowing the first lawn at 12:15 PM.

Since none of the given options match this time, it seems there might be an error in the information provided.