In this estimation, question gives your answers to one significant figure.
A) If a cash point dispenses a £10 note every second, how long would it take to dispense a
trillion pounds?
B) An aircraft carries 47 tonnes of cargo. If each banknote has a mass of 1g, what is the maximum value of £10 notes that fit into the plane?
So where is your attempt to do the problems?
my answer for question A was:
1*10^11 seconds which is 3000 years to 1 SF
is that correct? and I'm trying to solve question B
for part B I have got that the maximum value of £10 is 4700, by using the formula p=m/v
is that right? please help
To estimate the answers to these questions, we'll make some assumptions and use a simple calculation.
A) To estimate how long it would take to dispense a trillion pounds at a rate of £10 per second, we can divide 1 trillion pounds by 10 pounds per second.
1 trillion pounds / 10 pounds per second = 100 billion seconds
To convert this to a more meaningful unit of time, we can divide by the number of seconds in a year:
100 billion seconds / 60 seconds per minute / 60 minutes per hour / 24 hours per day / 365 days per year ≈ 3171 years
So, it would take approximately 3171 years to dispense a trillion pounds if a cash point dispensed a £10 note every second.
B) To estimate the maximum value of £10 notes that fit into the plane, we need to calculate the total mass of the cargo and then find the maximum number of £10 notes with an equivalent mass.
We know that each banknote has a mass of 1g, and the aircraft carries 47 tonnes of cargo. To convert tonnes to grams, we multiply by 1,000,000:
47 tonnes × 1,000,000 grams per tonne = 47,000,000 grams
Now, we divide the total mass of the cargo by the mass of each banknote:
47,000,000 grams / 1 gram per banknote = 47,000,000 banknotes
Since each banknote has a value of £10, the maximum value of £10 notes that fit into the plane is:
47,000,000 banknotes × £10 per banknote = £470,000,000
Therefore, the maximum value of £10 notes that fit into the plane is approximately £470 million.