Algebra

Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A sample of 1800 bacteria selected from this population reached the size of 2272 bacteria in five hours. Find the hourly growth parameter.

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  1. so
    number = a e^(kt)

    2272 = 1800 e^(5k)
    1.26222... = e^5k
    ln 1.26222... = 5k
    k = .04657.. <----- your hourly growth parameter

    the instantaneous rate of growth is appr 4.657% per hour.

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