Physics College

A see-saw 3.76 meters long perfectly balances on its own at its center. Two children get on the see-saw. One, weighing 345 N, sits at the left hand end. The other, sits 25.0 cm in from the right hand end. The see-saw is perfectly balanced with the children sitting in these locations. What is the weight of the child on the right?

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  1. sum moments about the pivot
    W*3.76/2-345(3.76/2-.25)=0
    solve for Weight W

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    bobpursley
  2. F1 * d1 = F2 * d2.
    345 * 3.76/2 = F2 * (3.76/2-0.25).
    F2 = ?.

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