cost price of article A is 200 more than cost price of B.A was sold at 10% loss and B at 25% profit. if overall profit profit earned after selling both article is 4% what is cp of article B?

Let n be the price of B. Then A is n+200. So:

.9(n+200)+1.25n=1.04(n+n+200)
Solve for n
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To find the cost price of article B, we need to solve this problem step by step. Let's begin:

1. Let's assume the cost price of article B is x.
2. According to the problem, the cost price of article A is 200 more than the cost price of article B. So, the cost price of article A is (x + 200).

Now, let's calculate the selling prices of both articles:

1. Article A was sold at a 10% loss. This means it was sold for 90% of its cost price. So, the selling price of article A is (90/100) * (x + 200).
2. Article B was sold at a 25% profit. This means it was sold for 125% of its cost price. So, the selling price of article B is (125/100) * x.

Next, let's calculate the overall cost price and overall selling price:

1. Overall cost price = Cost price of article A + Cost price of article B = (x + 200) + x = 2x + 200.
2. Overall selling price = Selling price of article A + Selling price of article B = (90/100) * (x + 200) + (125/100) * x.

We are given that the overall profit earned after selling both articles is 4%. This means the overall selling price should be 104% of the overall cost price. So, we can write the equation:

Overall selling price = 104% of overall cost price.

Substituting the values we found earlier for the overall selling price and overall cost price:

(90/100) * (x + 200) + (125/100) * x = (104/100) * (2x + 200).

By solving this equation, we can find the value of x, which represents the cost price of article B.