physic

two particles moving along x-axis in the same direction with uniform velocity is 8 metre per second and 4 metre per second initially the first particle is 21 m to the left of the origin and the second one is 7 m to the right of the origin to particle meets from the origin at a distance of

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  1. particle 1
    x = -21 + 8 t
    particle 2
    x = 7 + 4 t
    so
    -21 + 8 t = 7 + 4 t

    4 t = 28
    t = 4 seconds
    x = 7 + 16 = 23

    1. 👍 4
    2. 👎 37
  2. 1 st particle
    x+21=u¹t
    21+x=8t
    x=-21+8t....
    2 nd particle
    x-7=u²t
    x=7+4t
    equating 1st and 2 nd particles
    -21+8t=7+4t
    8t-4t=21-7
    4t=28
    t=28/4 = 7 sec
    SUBSTITUTION
    x=-21+8t
    x=-21+8(7)
    x= -21+56=35
    (or)
    x=7+4t
    x=7+4(7)
    x=7+28=35

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  3. Correct 😀😀

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  4. nice solution very easy understanding thanks

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  5. Very nice answer bro

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  6. Why u took x plus 21=u1t

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