|3-7x|=-6
6w-1/5 -3w=12w-16/15
(X-3)^2-3=-5
(X+3)^2+4(x+3)-5=0
|3-7x|=-6
trick question. || is never negative
6w-1/5 -3w=12w-16/15
w = 13/135
(6w-1)/5 -3w=(12w-16)/15
w = 1/3
(x-3)^2-3=-5
(x-3)^2 = -2
No solution, since square are never negative
(x+3)^2+4(x+3)-5=0
If u=x+3 then you have
u^2+4u-5=0
(u+1)(u-5)=0
So,
x+3 = -1 or x+3 = 5
x = -4 or 2