Algebra

y varies jointly as X and Z. y=64 when x=4 and z=8. Find y when x=8 and z=6

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  1. y = k ∙ x ∙ z

    When x = 4 , y = 64 and z = 8:

    y = k ∙ x ∙ z

    64 = k ∙ 4 ∙ 8

    64 = 32 k

    Divide both sides by 32

    64 / 32 = k

    2 = k

    k = 2

    When x = 8 and z = 6:

    y = k ∙ x ∙ z

    y = 2 ∙ x ∙ z

    y = 2 ∙ 8 ∙ 6

    y = 2 ∙ 48

    y = 96

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  2. y = kxz
    so, y/(xz) = k, a constant

    You want y such that

    y/(8*6) = 64/(4*8)
    y/48 = 2
    y = 96

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