1. Mr.Lim gave 3600 to his wife and two children altogether. His wife received $500 more than his son. His son received twice as much his daughter. How much did Mr. Lim's wife receive?

2. There were 4342 buttons altogether in three bags A B and C There were 18 more buttons in Bag B than in Bag A. There were 3 times as many buttons in Bag C as in Bag B. How many buttons were there in Bag A?

3.Louis had 135 action figures, Sam had 990 action figures and Jane had 570 action figures. after jane gave an equal number of action figures to both boys, Sam had 4 times as many action figures as Louis. How many action figures did jane have left?

1740 wife

1240 son
620 daughter
=3600

1. To solve this problem, let's assign variables to the unknown quantities. Let x represent the amount Mr. Lim's son received. Since his daughter received twice as much as his son, the daughter received 2x.

Given that Mr. Lim gave a total of 3600, the equation is: x + 2x + (2x + 500) = 3600.

Simplifying the equation, we have: 5x + 500 = 3600.

Next, subtract 500 from both sides of the equation: 5x = 3100.

Finally, divide both sides of the equation by 5 to solve for x: x = 620.

Therefore, Mr. Lim's wife received 2x + 500 = 2(620) + 500 = 1240 + 500 = $1740.

2. Let's assign variables to the quantities in question. Let x represent the number of buttons in Bag A. Since there were 18 more buttons in Bag B than Bag A, the number of buttons in Bag B is x + 18. Moreover, since there were 3 times as many buttons in Bag C as Bag B, the number of buttons in Bag C is 3(x + 18).

Given that the total number of buttons is 4342, the equation is: x + (x + 18) + 3(x + 18) = 4342.

Simplifying the equation, we have: x + x + 18 + 3x + 54 = 4342.

Combining like terms, we get: 5x + 72 = 4342.

Next, subtract 72 from both sides of the equation: 5x = 4270.

Finally, divide both sides of the equation by 5 to solve for x: x = 854.

Therefore, there were 854 buttons in Bag A.

3. Let's assign variables to represent the number of action figures. Let's call the number of action figures Jane gave away as x.

After Jane gave an equal number of action figures to both boys, Sam had 990 + x action figures, and Louis had 135 + x action figures.

Given that Sam had four times as many action figures as Louis, the equation is: 990 + x = 4(135 + x).

Expanding and simplifying the equation, we have: 990 + x = 540 + 4x.

Next, subtract x from both sides of the equation: 990 = 540 + 3x.

Then, subtract 540 from both sides of the equation: 450 = 3x.

Finally, divide both sides of the equation by 3 to solve for x: x = 150.

Therefore, Jane has 570 - 150 = 420 action figures left.

Louis had 135 action figures, Sam had 990 action figures and Jane had 570 action figures. after jane gave an equal number of action figures to both boys, Sam had 4 times as many action figures as Louis. How many action figures did jane have left?

Dawn and Emily each had the same length of ribbon. Both girls used their ribbons to make identical bows. Dawn made 12 bows and had 128 cm of ribbon left. Emily made 9 bows and had 176 cm of ribbon left. How many bows could Emily make with the ribbon she had left?

Hi ,jag how did you get the answer ?thanks

thank you so much for helping me solving my math problem

Did you get the other two ?

Make an attempt to translate the English into Math.

I will do #2 for you, then you show me how you did the other two, and I will check it for you

#2
"There were 18 more buttons in Bag B than in Bag A"
----> B = A+18
"There were 3 times as many buttons in Bag C as in Bag B"
----> C = 3B = 3(A+18) = 3A + 54

" There were 4342 buttons altogether in three bags A B and C"
----> A+B+C = 4342
A + A+18 + 3A+54 = 4342
5A + 72 = 4342
5A = 4270
A = 854
then B = A+18 = 854+18 = 872
and C = 2616

check: is 854+872+2616 = 4342 ? YES
is 872 greater than 854 by 18 ? YES
is 2616 three times as large as 854 ? YES

My answer is correct!

Mr.Lim gave $3600 to his wife and two children altogether.His wife received $500more than his son. His Son received twice as much as his daughter. how much did Mr.Lim's wife receive?

Solution:
Wife + Son + Daughter = $3600
Wife - $500 = Son receive
Daughter = 2x the Son's receive

3÷ $3600 = $1200

Wife = $1200
Son = ($1200 -$500) = $700
Son receive 2x as his daughter
Son = $700 × 2 = $1400
Daughter ($1200-$700) = $500
Daughter $500

Wife received $1700
Son received $1400
Daughter received $500
Total $3600