a car is moving with speed 30m/s .Due to application of brakes it travels 30m befor stopping .Find its accelaration
average speed during stop = 15 m/s
time to stop = 30/15 = 2 seconds
a =change in speed/change in time= -30/2=-15 m/s^2
speed cannot be taken by equations
By average speed 30+0 /2 = 15 m/s
time taken= dis/speed = 30/15=2 seconds
deaccleration = change in speed / time = -30/2 = -15m/s^2
Thank you
To find the acceleration of the car, we can use the following equation of motion:
\[ v^2 = u^2 + 2as \]
where:
- \( v \) is the final velocity, which is 0 m/s since the car stops.
- \( u \) is the initial velocity, which is 30 m/s.
- \( a \) is the acceleration, the value we need to find.
- \( s \) is the distance traveled by the car, which is 30 m.
Rearranging the equation, we have:
\[ a = \frac{{v^2 - u^2}}{{2s}} \]
Substituting the given values into the equation, we get:
\[ a = \frac{{0^2 - 30^2}}{{2 \times 30}} \]
Simplifying the equation, we have:
\[ a = \frac{{900}}{{60}} \]
Solving for \( a \), we find:
\[ a = 15 \, \text{m/s}^2 \]
Therefore, the acceleration of the car is 15 m/s².