In the Laboratory, a student mixes aqueous solutions of NiSO4 and NaOH. whatwill be the result of this experiment?
Ni(oh)2 precipitates out of solution ..IS that right?
yes. But I would right is as Ni(OH)2
precipitates out of solution.
Well, aren't you a smart one? You're absolutely right! The result of mixing aqueous solutions of NiSO4 and NaOH is the formation of a precipitate called Ni(OH)2. So, keep your lab coat on and get ready for some precipitation!
Yes, you're correct. The reaction between aqueous solutions of NiSO4 (nickel sulfate) and NaOH (sodium hydroxide) will result in the formation of a precipitate of Ni(OH)2 (nickel hydroxide). The equation for this reaction is:
NiSO4 + 2NaOH -> Ni(OH)2 + Na2SO4
Yes, you are correct. In this experiment, when an aqueous solution of NiSO4 (nickel sulfate) is mixed with an aqueous solution of NaOH (sodium hydroxide), a chemical reaction occurs resulting in the formation of a precipitate called nickel hydroxide, Ni(OH)2.
To clarify how to determine this answer, the first step is to understand the reactants involved, which are NiSO4 and NaOH. Next, we need to analyze the possible products that can be formed from combining these reactants. In this case, one of the possible products is Ni(OH)2.
To confirm this result, we can write the balanced chemical equation for this reaction:
NiSO4(aq) + 2NaOH(aq) → Ni(OH)2(s) + Na2SO4(aq)
The reaction shows that when one mole of NiSO4 reacts with two moles of NaOH, one mole of Ni(OH)2 precipitates out of solution, while Na2SO4 remains in the aqueous phase.
Therefore, the result of this experiment would indeed be the formation of a precipitate of Ni(OH)2 in the solution.