ci and si for certain sum at certain rate for 2 yrs are 220 and 200.what is principal for these interest?
p((1+r)^2-1) = 220
p(2r) = 200
now just solve for p and r.
To find the principal for these interest, we need to use the compound interest (CI) formula. The compound interest formula is given as:
CI = P(1 + r/n)^(nt) - P
Where:
CI = Compound interest
P = Principal
r = Annual interest rate (in decimal form)
n = Number of times interest is compounded per year
t = Number of years
In this case, we have the values of CI for 2 years, which are 220 and 200. Let's assume the annual interest rate is 'R', and the number of times interest is compounded per year is 'n' (which is not provided).
Using the formula, we can set up two equations based on the given information:
220 = P(1 + R/n)^(2n) - P
200 = P(1 + R/n)^(2n) - P
Simplifying the equations, we get:
P(1 + R/n)^(2n) - P = 220
P(1 + R/n)^(2n) - P = 200
Since the values of the interest rates and the number of times interest is compounded per year ('R' and 'n') are not given, it is not possible to directly solve these equations to find the principal amount.
To solve this problem and find the principal amount, we would need additional information, such as the annual interest rate and the number of times interest is compounded per year.