Factor Completely (x-4(x^2+3)
Perform the indicated operations (-(7x^3+6x^2-11x+13) +(19x^3-11x^2+7-17
Find The Product (2x-1)- (-x^2-4x+3)
for the first one, if you mean (x-4)(x^2+3) then it is already factored.
I am not going to second-guess what you mean for the second, you have 3 opening brackets, and only one closing bracket, so it makes no sense.
for the third you are asking for the product, which is a multiplication answer, but you typed a subtraction.
So which is it?
After showing some unnecessary "attitude" towards MS Sue in your previous post, you shouldn't be surprised if you don't get an over-enthusiastic response from the other volunteer tutors.
well try both answers
To factor completely (x-4)(x^2+3), we can use the distributive property to multiply the term outside the parentheses to each term inside the parentheses.
(x-4)(x^2+3) = x(x^2+3) - 4(x^2+3)
Next, we can simplify further by using the distributive property again to multiply the remaining terms:
= x^3 + 3x - 4x^2 - 12
Now, we can rearrange the terms in descending order of the degrees of x:
= x^3 - 4x^2 + 3x - 12
So, the factored form of (x-4)(x^2+3) is x^3 - 4x^2 + 3x - 12.
For the second question, to perform the indicated operations (-(7x^3+6x^2-11x+13) +(19x^3-11x^2+7-17), we first need to distribute the negative sign to each term inside the parentheses:
= -7x^3 - 6x^2 + 11x - 13 + 19x^3 - 11x^2 + 7 - 17
Next, we can combine like terms:
= (-7x^3 + 19x^3) + (-6x^2 - 11x^2) + (11x) + (-13 + 7 - 17)
= 12x^3 - 17x^2 + 11x - 23
Therefore, the result of performing the indicated operations is 12x^3 - 17x^2 + 11x - 23.
Lastly, to find the product of (2x-1) and (-x^2-4x+3), we use the distributive property again:
(2x - 1)(-x^2 - 4x + 3) = 2x(-x^2) + 2x(-4x) + 2x(3) + (-1)(-x^2) + (-1)(-4x) + (-1)(3)
= -2x^3 - 8x^2 + 6x + x^2 + 4x - 3
Now, we can combine like terms:
= -2x^3 - 7x^2 + 10x - 3
Therefore, the product of (2x-1) and (-x^2-4x+3) is -2x^3 - 7x^2 + 10x - 3.