A certain deck of cards consists of only 10's, Jacks, Queens, and Kings, and is divided up evenly in a 52 card deck. what is the probablity of NOT drawing a jack? HELP ASAP!!!!!!!

3/4

Thank YOU

You are welcome.

If I interpret the question correctly, you are adding 16 new cards to a complete deck of 52.

So the new deck now contains 8 Jacks
prob(Jack) = 8/68 = 2/17
prob(not a Jack) = 1 - 2/17 = 15/17

"is divided up evenly in a 52 card deck" : poor wording

To find the probability of not drawing a jack from the deck, we first need to determine the total number of cards in the deck and the number of jacks in the deck.

In a standard 52-card deck, there are four suits: hearts, diamonds, clubs, and spades. Each suit contains one jack, which means there are a total of four jacks in the deck.

The total number of cards in the deck is 52.

To find the probability of not drawing a jack, we can calculate the number of cards that are not jacks and divide it by the total number of cards in the deck.

Number of cards that are not jacks = Total number of cards - Number of jacks
= 52 - 4
= 48

Now, we can calculate the probability:

Probability of not drawing a jack = Number of cards that are not jacks / Total number of cards
= 48 / 52
= 12 / 13

Therefore, the probability of not drawing a jack from the deck is 12/13, which is approximately 0.923 or 92.3%.