What is the energy of electron 4th exicted state of of be3+ ion if energy of electron in ground state
To determine the energy of the 4th excited state of the Be3+ ion, we need to know the energy of the ground state electron. However, the energy of the ground state electron is not provided in your question.
The energy levels of an electron in a hydrogen-like ion (such as Be3+) can be calculated using the formula:
Eₙ = -13.6 eV / n²
Where Eₙ represents the energy of the electron in the nth energy level and n is the principal quantum number, representing the energy level.
Assuming that the energy of the ground state electron in the Be3+ ion is given as -13.6 eV (which is the energy of the ground state electron in a hydrogen atom), we can calculate the energy of the 4th excited state electron:
E₄ = -13.6 eV / (4²)
= -13.6 eV / 16
= -0.85 eV
Therefore, if the energy of the electron in the ground state of the Be3+ ion is -13.6 eV, the energy of the electron in the 4th excited state would be approximately -0.85 eV.