a die is thrown twice, find the probability of getting two 5’s. Be sure to represent your answer as a fraction in simplest form!
there are 6 possible outcomes, and only one is a success, so
P(5) = 1/6
Now you want two independent events, so just multiply their probabilities.
Of the 36 possible outcomes, only 1 is a success...
Ok so first you have to find the Number of successful outcomes over Total number of possible outcomes. So P(two 5s) is equal to 1/6 then you times the denominator by the same number to get 1/36.
Throwing a die twice can be quite dicey, but let's calculate the probability of getting two 5's.
A fair die has 6 sides, numbered 1 through 6. The probability of rolling a 5 on one throw is 1/6 since there's only one number 5. So the probability of getting a 5 on two consecutive throws is (1/6)*(1/6) = 1/36.
Therefore, the probability of getting two 5's is 1/36, which is as simple as it gets!
To find the probability of getting two 5's when throwing a die twice, we need to determine the total number of possible outcomes and the number of favorable outcomes.
Total number of outcomes when throwing a die twice = 6 * 6 = 36 (since each throw has 6 possible outcomes)
Number of favorable outcomes = 1 (since there is only one possibility to get a 5 in each throw)
Therefore, the probability of getting two 5's is 1/36.
To find the probability of getting two 5's when a die is thrown twice, we need to consider two scenarios:
1. The first throw results in a 5, and the second throw also results in a 5.
2. The first throw does not result in a 5, but the second throw does result in a 5.
Let's calculate the probability for each scenario:
Scenario 1:
The probability of getting a 5 on the first throw is 1/6 because there is only one favorable outcome (rolling a 5) out of six possible outcomes (rolling numbers 1-6).
The probability of getting a 5 on the second throw is also 1/6 since we assume that each throw is independent.
To find the probability of both events occurring, we multiply the individual probabilities together:
1/6 * 1/6 = 1/36
Scenario 2:
The probability of not getting a 5 on the first throw is 5/6 because there are five unfavorable outcomes (numbers 1, 2, 3, 4, and 6) out of six possible outcomes.
The probability of getting a 5 on the second throw is still 1/6.
Again, we multiply the individual probabilities together:
5/6 * 1/6 = 5/36
Finally, we add the probabilities of both scenarios together because they are mutually exclusive events:
1/36 + 5/36 = 6/36 = 1/6
Therefore, the probability of getting two 5's when a die is thrown twice is 1/6.