Ricky had come limes. he gave 25% of the limes to roberta and sold Tonia 2/9 of the remainder. He remained with 280 limes. Calculate

a) how many limes Ricky had at first

b) Tonia gave .375 of her limes to her mother. How many limes did Tonia keep for herself?

c) Calculate the percent of limes ricky gave away and sold rounded off to the nearest percentage.

the 25% + 2/9 of the remaining 75% add up to

1/4 + (2/9)(3/4) = 9/36 + 6/36 = 15/36 = 5/12

So, if he started out with x limes, then
7/12 x = 280

and so on

To solve this problem, we'll break it down step by step.

a) How many limes Ricky had at first:

1) Ricky gave 25% of the limes to Roberta. This means he gave away 0.25 (25%) of the limes, leaving 0.75 (100% - 25%) remaining.

2) Ricky then sold 2/9 of the remainder to Tonia. This means he sold 2/9 * 0.75 = 0.1667 (approximately) of the remaining limes to Tonia.

3) After selling the limes to Tonia, Ricky was left with 280 limes. So, we can write the equation: 0.75 - 0.1667 = 280.

4) Solving this equation, we find that the initial number of limes Ricky had is approximately: 0.5833 * 280 = ~162.917.

Therefore, Ricky had approximately 162 limes at first.

b) How many limes did Tonia keep for herself:

1) Tonia received 2/9 of the remaining limes. From step 2 above, we know that the remaining limes after Ricky gave 25% to Roberta was 0.75.

2) Tonia received 2/9 * 0.75 = 0.1667 (approximately) of the remaining limes.

3) But Tonia gave 0.375 (37.5%) of her limes to her mother. So, she kept 1 - 0.375 = 0.625 (62.5%) of the limes for herself.

Therefore, Tonia kept approximately 0.625 * 0.1667 = ~0.1042 portion of the limes for herself.

c) Calculate the percentage of limes Ricky gave away and sold:

1) Ricky gave 25% of the limes to Roberta. This is a straightforward calculation.

2) Ricky sold 2/9 * 100% = ~22.22% of the limes to Tonia.

3) Adding these two percentages together, we get approximately 25% + 22.22% = ~47.22%.

Therefore, Ricky gave away and sold approximately 47.22% of the limes.