A cake and three ice creams together cost $210. Mary bought a cake and two ice creams for $200.
a) Calculate the cost of 1 ice cream
b) the cost of the cake
c) the cost of 3 cakes and 5 ice creams
The cost of 1 ice-cream
a) Well, well, well, looks like we've got ourselves a sweet little math problem. Let's solve it, shall we? If Mary bought a cake and two ice creams for $200, and we know that a cake and three ice creams together cost $210, we can subtract the price of two ice creams from the total price she paid to find the cost of one ice cream. So, $210 minus $200 equals $10. Therefore, the cost of one ice cream is $10. Now, that's pretty cool!
b) Now that we know the cost of one ice cream is $10 and Mary bought a cake and two ice creams for $200, we can subtract the price of the two ice creams from the total price she paid to find the cost of the cake. So, $200 minus (2 times $10) equals $180. Hence, the cost of the cake is $180. Looks like Mary didn't go overboard with the cake, but hey, it's still a tasty treat!
c) To calculate the cost of three cakes and five ice creams, we can multiply the cost of one cake by three and the cost of one ice cream by five and then add the two results together. So, (1 cake times $180) plus (5 ice creams times $10) equals $180 + $50 = $230. Ta-da! The cost of three cakes and five ice creams is $230. In the words of a famous clown, "That's a lot of sweet treats for a jolly good time!"
17
The cost of 3 cakes and 5 ice-cream
How did u get 17
To solve this problem, we can use a system of equations. Let's assign variables to the unknowns:
Let x be the cost of a cake.
Let y be the cost of an ice cream.
From the problem statement, we have two equations:
1) "A cake and three ice creams together cost $210:"
x + 3y = 210
2) "Mary bought a cake and two ice creams for $200:"
x + 2y = 200
Now we can solve this system of equations to find the solutions to the problem.
a) Calculate the cost of 1 ice cream:
To find the cost of one ice cream (y), we need to solve the system of equations. Subtract equation 1 from equation 2:
x + 2y - (x + 3y) = 200 - 210
x + 2y - x - 3y = -10
-y = -10
y = 10
Therefore, the cost of one ice cream is $10.
b) Calculate the cost of the cake:
Substitute the value of y into either of the original equations to solve for x:
x + 3(10) = 210
x + 30 = 210
x = 210 - 30
x = 180
Therefore, the cost of the cake is $180.
c) Calculate the cost of 3 cakes and 5 ice creams:
To find the cost of 3 cakes and 5 ice creams, we can multiply the respective costs by the quantities:
Cost of 3 cakes = 3 * $180 = $540
Cost of 5 ice creams = 5 * $10 = $50
Therefore, the cost of 3 cakes and 5 ice creams is $540 + $50 = $590.
since the only difference is an ice cream, it clearly cost $10
That means that the cake was $200
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