There were 1100 apples at a fruit stall there were 220 more apples than mangoes how many apples and mangoes were there altogether?
well, there were 1100-220=880 mangos, so ...
Let's denote the number of mangoes as "m" and the number of apples as "a".
We know that there were 220 more apples than mangoes, so we can write the equation:
a = m + 220
We also know that there were 1100 apples in total.
So, we can write another equation:
a + m = 1100
Now, we can solve these two equations simultaneously to find the values of "a" and "m".
Substituting the value of "a" from the first equation into the second equation, we have:
(m + 220) + m = 1100
Simplifying the equation by combining like terms, we get:
2m + 220 = 1100
Next, we isolate the term with "m" by subtracting 220 from both sides:
2m = 1100 - 220
Simplifying further, we have:
2m = 880
Finally, we divide both sides of the equation by 2 to solve for "m":
m = 880 / 2
m = 440
Therefore, there were 440 mangoes at the fruit stall.
To find the number of apples, we substitute the value of "m" back into the first equation:
a = m + 220
a = 440 + 220
a = 660
Therefore, there were 660 apples at the fruit stall.
Altogether, there were 440 mangoes and 660 apples.
To find the number of apples and mangoes altogether, we need to set up an equation based on the information given.
Let's assume the number of mangoes is "x".
Since there were 220 more apples than mangoes, the number of apples would be "x + 220".
We know that the total number of apples and mangoes is 1100, so we can create the equation:
x + (x + 220) = 1100
To solve this equation, we can simplify it:
2x + 220 = 1100
Next, we subtract 220 from both sides of the equation:
2x = 880
Now, divide both sides of the equation by 2:
x = 440
Therefore, there were 440 mangoes.
To find the number of apples, substitute the value of "x" back into the equation:
x + 220 = 440 + 220 = 660
So, there were 660 apples.
Altogether, there were 440 mangoes and 660 apples.