If the percentage of water of crystallization in MgSO4.xH2O is 13% , then what is the value of 'X'.
Then %MgSO4 is 100-13=87.
So 87/molar mass MgSO4 = ?
and 13/molar mass H2O = ?
Now find the ratio of 1 mol MgSO4 to x mols H2O.
Post your work if you get stuck.
To find the value of 'X', we first need to understand the concept of water of crystallization.
Water of crystallization refers to the water molecules that are present in a crystalline compound. These water molecules are chemically bound to the compound and can be removed by heating or other methods. The value of 'X' in the formula MgSO4.xH2O represents the number of water molecules per mole of the compound.
Given that the percentage of water of crystallization in MgSO4.xH2O is 13%, this means that for every 100 grams of the compound, 13 grams of water are present.
To calculate the value of 'X', we can calculate the molar mass of the water (H2O) and the molar mass of the compound (MgSO4.xH2O). Then, by comparing the masses of water and the compound, we can find the ratio of water to the compound and determine the value of 'X'. Here's how:
1. Calculate the molar mass of water (H2O):
- The atomic mass of hydrogen (H) is approximately 1 gram/mole.
- The atomic mass of oxygen (O) is approximately 16 grams/mole.
- Therefore, the molar mass of water (H2O) is (2 * 1) + 16 = 18 grams/mole.
2. Determine the molar mass of the compound (MgSO4.xH2O):
- The atomic mass of magnesium (Mg) is approximately 24 grams/mole.
- The atomic mass of sulfur (S) is approximately 32 grams/mole.
- The atomic mass of oxygen (O) is approximately 16 grams/mole.
- The molar mass of MgSO4 is (24) + (32) + (4 * 16) = 120 grams/mole.
- Let's assume the molar mass of 'x' moles of water is y grams/mole.
3. Calculate the mass of water and the compound:
- Given that the percentage of water of crystallization is 13%, this means that for every 100 grams of the compound, 13 grams of water are present.
- Therefore, the mass of the compound is 100 grams - 13 grams = 87 grams.
- The mass of 'x' moles of water is x * y grams.
4. Set up an equation based on the ratio of water to compound:
- The mass of 'x' moles of water is x * y grams.
- The mass of the compound is 87 grams.
- Since the compound contains water of crystallization, the sum of the masses of water and the compound should add up to the given mass of the compound.
- Therefore, we have the equation: x * y + 87 = 87
5. Solve for 'X':
- Subtracting 87 from both sides of the equation gives: x * y = 0
- Since 'x' and 'y' represent the number of moles, they cannot be zero. Therefore, 'x' must be 0.
- Therefore, the value of 'X' is 0.
Thus, the value of 'X' in the formula MgSO4.xH2O is 0.