2SO2(g) + O2(g) ---> 2SO3
It says that 12.0 L of sodium trioxide are produced at 100 degrees celcius. What volume of oxygen is produced?
How would I go about doing this. I was going to use PV=nRT but I dunno the pressure so I can't find the moles. What do I do?
The equation tells us (if the reaction goes to completion) that 1 mol O2 produces 2 mols SO3. Those are the coefficients in the balanced equation. Therefore,
12 L SO3 x (1 mol O2/2 mol SO3) = 6 L O2.
a. SO3 is sulfur trioxide, not sodium trioxide.
b. There is no oxygen produced. Oxygen is on the reactant side.
c. In gaseous reactions, it isn't necessary to convert to mols. You may use volume directly; i.e., 12.0 L SO3 produced means 6.0 L oxygen were used (if the reaction goes to completion).
d. note the correct spelling of Celsius.
How do you know it was 6 L of oxygen? I don't understand :S
To find the volume of oxygen produced in the given reaction, you can use the stoichiometry of the balanced equation and the ideal gas law equation. Let's break it down step by step:
1. Start with the balanced equation: 2SO2(g) + O2(g) ---> 2SO3(g)
2. Determine the molar ratio between the reactants and products. From the balanced equation, you can see that for every 2 moles of SO2 reacted, 1 mole of O2 is produced.
3. Convert the given volume of sodium trioxide (SO3) to moles. Since the reaction is given at 100 degrees Celsius, we need to assume that the volume is measured under those conditions. Use the ideal gas equation:
PV = nRT
Where:
P = pressure (which you mentioned is not given)
V = volume
n = number of moles
R = ideal gas constant
T = temperature in Kelvin (remember to convert from Celsius)
However, since you don't know the pressure, you won't be able to find the moles directly from this equation.
4. Since you have the volume of SO3 (12.0 L) and want to find the volume of O2, you can use the molar ratio from step 2 to indirectly find the number of moles of O2.
2SO2(g) + O2(g) ---> 2SO3(g)
For every 2 moles of SO2 reacted, 1 mole of O2 is produced.
Therefore, if x moles of SO3 are produced, then x/2 moles of O2 are produced.
5. To find the number of moles of O2, convert the volume of SO3 to moles using the ideal gas law equation. Remember to convert the temperature to Kelvin.
6. Once you have the number of moles of O2, you can use the ideal gas law equation again to find the volume of O2. But this time, instead of finding moles, you'll be solving for the volume (V).
PV = nRT
The pressure (P) is still unknown, so you'll have to leave it as a variable.
7. So, in conclusion, you won't be able to find the actual volume of O2 produced without knowing the pressure of the reaction. However, you can use the molar ratio and the volume of SO3 to find the number of moles of O2 and leave the volume as a variable.