If the diameter of a circle P is 40 percent of the diameter of circle Q, then the area of circle P is what percentage of the area of circle Q?
Not enought information given right?
dP = diameter of circle P
dQ = diameter of circle Q
AP = area of circle P
AQ = area of circle Q
40% = 40 / 100 = 0.4
dP = 0.4 dQ
Area of circle = d² ∙ π /4
AQ = dQ² ∙ π /4
AP = dP² ∙ π /4
AP = ( 0.4 dQ )² ∙ π /4
AP = 0.16 dQ²∙ π /4
AP / AQ = 0.16 = 16%
thanks
DOESNT HELP! AT ALL!
Actually, we can determine the answer to this question without needing any additional information.
The ratio between the areas of two circles is equal to the square of the ratio between their diameters. In this case, the diameter of circle P is 40% of the diameter of circle Q.
To find the ratio between their diameters, we convert 40% to a decimal by dividing it by 100:
40 / 100 = 0.4
So, the diameter of circle P is 0.4 times the diameter of circle Q.
Now, to find the ratio of their areas, we square this ratio:
(0.4)^2 = 0.16
Therefore, the area of circle P is 16% of the area of circle Q.