According to the following reaction, how many grams of tetraphosphorus decaoxide are required for the complete reaction of 26.5 grams of perchloric acid (HClO4)?
perchloric acid (HClO4) (aq) + tetraphosphorus decaoxide (s) ---> phosphoric acid (aq) + dichlorine heptaoxide (l)
_____ grams tetraphosphorus decaoxide
To determine the number of grams of tetraphosphorus decaoxide required, we need to use the balanced chemical equation and the molar masses of the compounds involved.
First, let's find the molar mass of perchloric acid (HClO4):
HClO4 = (1 * 1.01) + (1 * 35.45) + (4 * 16.00) = 100.46 g/mol
Next, let's find the molar mass of tetraphosphorus decaoxide (P4O10):
P4O10 = (4 * 30.97) + (10 * 16.00) = 283.88 g/mol
Now, we can set up a ratio using the coefficients from the balanced equation and the molar masses of the compounds:
1 mol of HClO4 reacts with 1 mol of P4O10
100.46 g of HClO4 reacts with 283.88 g of P4O10
Using the given information that 26.5 grams of HClO4 are present, we can calculate the grams of P4O10 required:
(26.5 g HClO4) * (283.88 g P4O10 / 100.46 g HClO4) = 74.918 grams of P4O10
Therefore, approximately 74.918 grams of tetraphosphorus decaoxide are required for the complete reaction of 26.5 grams of perchloric acid (HClO4).
To determine the number of grams of tetraphosphorus decaoxide (P4O10) required for the reaction, we need to use stoichiometry.
Step 1: Write the balanced equation for the reaction:
perchloric acid (HClO4) (aq) + tetraphosphorus decaoxide (P4O10) (s) --> phosphoric acid (H3PO4) (aq) + dichlorine heptaoxide (Cl2O7) (l)
Step 2: Find the molar mass of HClO4 and P4O10:
Molar mass of HClO4 = (1.01 g/mol * 1) + (35.45 g/mol * 1) + (16.00 g/mol * 4) = 100.46 g/mol
Molar mass of P4O10 = (30.97 g/mol * 4) + (16.00 g/mol * 10) = 283.89 g/mol
Step 3: Determine the molar ratio between HClO4 and P4O10:
From the balanced equation, we can see that the stoichiometric ratio of HClO4 to P4O10 is 1:1.
Step 4: Calculate the number of moles of HClO4:
Number of moles = mass / molar mass
Number of moles of HClO4 = 26.5 g / 100.46 g/mol = 0.264 mol
Step 5: Use the molar ratio to determine the number of moles of P4O10:
Since the stoichiometric ratio is 1:1, the number of moles of P4O10 is also 0.264 mol.
Step 6: Convert the number of moles of P4O10 to grams:
Mass = number of moles x molar mass
Mass of P4O10 = 0.264 mol x 283.89 g/mol = 74.74 grams
Therefore, approximately 74.74 grams of tetraphosphorus decaoxide (P4O10) are required for the complete reaction of 26.5 grams of perchloric acid (HClO4).
The equation is not complete.
P4O10 + 2HClO4 + 5H2O ==> 4H3PO4 + Cl2O7
mols HClO4 = grams/molar mass = ?
mols P4O10 = 1/2 mols HClO4
g P4O10 = mols x molar mass = ?
Poat your work if you get stuck.