what is the molarity of a solution of KNO3(molecular mass=101) that contains 404 grams of KNO3 in 2.00 liters of solution?
A. 1.00M
b. 2.00M
c. 0.500M
d. 4.00M
The definition of molarity is #mols/Liter of solution. Convert 404 g KNO3 to mols (mols = g/molar mass) and plug into the definition.
is it B?
You are right again.
The answer is B. 2.00M
Yes, the answer is B. To calculate the molarity of a solution, we need to first convert the mass of the solute to moles, and then divide by the volume of the solution in liters.
First, we need to find the number of moles of KNO3 in the solution. The molar mass of KNO3 is 101 g/mol. Therefore, the number of moles of KNO3 can be calculated as follows:
Number of moles = mass of KNO3 / molar mass of KNO3
Number of moles = 404 g / 101 g/mol
Number of moles = 4 mol
Next, we divide the number of moles by the volume of the solution in liters:
Molarity = Number of moles / Volume of solution
Molarity = 4 mol / 2.00 L
Molarity = 2.00 M
Therefore, the molarity of the solution of KNO3 is 2.00 M.
To find the molarity of a solution, you need to calculate the number of moles of solute (KNO3) and divide it by the volume of the solution in liters.
The molar mass of KNO3 (potassium nitrate) is 101 g/mol.
First, calculate the number of moles of KNO3 in the solution:
Number of moles = Mass of KNO3 / Molar mass of KNO3
= 404 g / 101 g/mol
= 4 mol
Next, calculate the molarity using the formula:
Molarity = Number of moles / Volume of solution in liters
= 4 mol / 2.00 L
= 2.00 M
Therefore, the molarity of the solution is 2.00 M, which corresponds to option B.