math,algebra

can someone help me i've tried different numbers but i can come out to factor this:

2b^2+6b-216=0

why don't you divide the equation by 2 to get b^2+3b-108=0

now by trial and error, can you find two factors of 108 that have a difference of 3?

(b-9)(2b+24)

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asked by jacky

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