An object is dropped from top of a 430 foot building,it's height in feet at time t seconds is given by polynomial -16t^2+430.find the height of the object when t=5 second.
just plug in 5 for t and evaluate it.
I did the answer was 270,but was wrong.
Too bad you didn't show your work...
-16(5^2)+430
= -16 * 25 + 430
= -400 + 430
= 30
How ever did you get 270?
5^2 is not 10
To find the height of the object when t=5 seconds, we need to substitute t=5 into the equation -16t^2 + 430 and solve for the height.
First, let's substitute t=5 into the equation: -16(5)^2 + 430.
Simplifying this: -16(25) + 430.
Multiplying: -400 + 430.
Adding: 30.
Therefore, when t=5 seconds, the height of the object is 30 feet.