suppose that you have a n unlimited supply of copper II chloride to react with iron. how manyt moles of copper would be produced by reacting 34.0g of iron with the copperII chloride solution?
Fe + CuCl2 ==> FeCl2 + Cu
34.0 g Fe/aromic mass Fe = mols Fe.
mols Cu = mols Fe since 1 mol Fe reacts with 1 mol CuCl2.
how many mole of iron would have been used up if 45.0g of copper were to be produced?
Well, if you have an unlimited supply of copper II chloride, I suppose you could produce an infinite amount of copper! But let's focus on the question at hand. To find out how many moles of copper would be produced, we need to use some good old chemistry.
The molar mass of iron (Fe) is approximately 55.85 g/mol, so 34.0g of iron is about 34.0 g / 55.85 g/mol, which is roughly 0.61 moles of iron.
Now, we need to figure out the mole ratio between copper II chloride (CuCl2) and copper (Cu). From the balanced equation of the reaction, we see that the mole ratio between CuCl2 and Cu is 1:1.
Therefore, the amount of copper produced would be roughly 0.61 moles as well.
But hey, don't forget that I mentioned earlier that you have an unlimited supply of copper II chloride. So, technically, you could produce an infinite amount of copper! Now you'll have more copper than you'll know what to do with. Time to start a clownish copper empire, maybe?
To find the number of moles of copper produced, we need to set up a balanced chemical equation for the reaction between iron and copper(II) chloride:
2 Fe + 3 CuCl2 -> 2 FeCl3 + 3 Cu
From the balanced equation, we can see that the molar ratio of iron to copper is 2:3. This means that for every 2 moles of iron reacted, 3 moles of copper are produced.
Now, let's calculate the number of moles of iron in 34.0g of iron. We need to know the molar mass of iron to perform the calculation. The molar mass of iron (Fe) is approximately 55.8g/mol.
Number of moles of iron = mass of iron / molar mass of iron
Number of moles of iron = 34.0g / 55.8g/mol
Number of moles of iron ≈ 0.61 mol
Since the molar ratio of iron to copper is 2:3, we can calculate the moles of copper produced using the ratio:
Number of moles of copper = (Number of moles of iron) * (3 moles of copper / 2 moles of iron)
Number of moles of copper = 0.61 mol * (3/2)
Number of moles of copper ≈ 0.91 mol
Therefore, reacting 34.0g of iron with an unlimited supply of copper(II) chloride would produce approximately 0.91 moles of copper.