49gm of sulphuric acid is present in 100ml aq. Solution .What is the molarity of sulphuric acid?
To calculate the molarity of a solution, you need to know the number of moles of the solute and the volume of the solution.
First, we need to calculate the number of moles of sulphuric acid (H2SO4) using its molar mass.
The molar mass of sulphuric acid (H2SO4):
2(1.008 g/mol for hydrogen) + 32.07 g/mol for sulfur + 4(16.00 g/mol for oxygen) = 98.09 g/mol.
Next, we can calculate the number of moles of sulphuric acid:
Number of moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4
Number of moles of H2SO4 = 49 g / 98.09 g/mol
Number of moles of H2SO4 = 0.5 mol
Finally, we can calculate the molarity of the sulphuric acid solution:
Molarity (M) = Number of moles of solute / Volume of solution (in liters)
Molarity (M) = 0.5 mol / 0.1 L
Molarity (M) = 5 mol/L
Therefore, the molarity of the sulphuric acid solution is 5 M.
To find the molarity of the sulphuric acid solution, we'll use the formula:
Molarity (M) = Number of moles (n) / Volume of solution (V)
First, we need to calculate the number of moles using the given mass and the molar mass of sulphuric acid (H2SO4). The molar mass of sulphuric acid is:
H2 = 2(1) = 2 g/mol
S = 32 g/mol
O4 = 4(16) = 64 g/mol
Adding these together: 2 + 32 + 64 = 98 g/mol
Next, we calculate the number of moles of sulphuric acid:
Number of moles (n) = Mass / Molar mass
n = 49 g / 98 g/mol
n = 0.5 mol
Now that we know the number of moles, we can calculate the molarity of the solution:
Molarity (M) = n / V
V = 100 ml = 100 cm³ (since 1 ml = 1 cm³)
M = 0.5 mol / 100 cm³
However, we need to convert the volume to liters because the unit for molarity is moles per liter:
M = 0.5 mol / 0.1 L
M = 5 mol/L
Therefore, the molarity of the sulphuric acid solution is 5 M.
49g in 100 mL solution =>
490g in 1000 mL solution.
molecular mass of H2SO4=2+32+64=98
Molarity = (mass/L)/molecular mass = ?M