math

The following data represent the​ high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population.
TemperatureTemperature
​50-59
​60-69
​70-79
​80-89
​90-99
​100-109

DaysDays
1
309
1433
1521
412
14
​(a) Approximate the mean and standard deviation for temperature.
muμequals=
nothing

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  1. Find the mean first = sum of scores/number of scores

    55*1 + 65*309 + 75*1433....

    Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

    Standard deviation = square root of variance

    I'll let you do the calculations.

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