Two simmers are swimming in a lake. Swimmer A starts swimming at a speed of 1m/sec towards the shore from a distance of 30 m. Swimmer B starts swimming towards the shore from 10m behind swimmer A but he swims at 1.5m/sec. Which swimmer will arrive at the shore first ?
40m/1.5sec = 26.7 sec
30m/1sec = 30 sec
So Swimmer B will arrive at the shore first?
Is 26.7 seconds less than 30?
Yes it is
To determine which swimmer will arrive at the shore first, we need to calculate the time it takes for each swimmer to reach the shore.
Let's start with Swimmer A:
Distance = 30 meters
Speed = 1 meter per second
Using the formula: Time = Distance / Speed
Time taken by Swimmer A = 30 meters / 1 meter per second
Time taken by Swimmer A = 30 seconds
Now, let's calculate the time taken by Swimmer B:
Distance = Distance between Swimmer A and Swimmer B = 10 meters (Swimmer B starts 10 meters behind Swimmer A)
Speed = 1.5 meters per second
Time taken by Swimmer B = Distance / Speed
Time taken by Swimmer B = 10 meters / 1.5 meters per second
Time taken by Swimmer B ≈ 6.67 seconds
Comparing the times, we see that Swimmer B will arrive at the shore first since it takes 6.67 seconds whereas Swimmer A takes 30 seconds.