What is the final temperature when 8.1 x 105 J are added to 1.50 kg of ice at 0.0 °C?
to melt ice at 0 C requires 334,000 Joules/kg
so we use 501,000 Joules for melting at 0 C
501,000 = 5.01*10^5
so we still have 3.11*10^5 JOules to heta the water
4190 Joules to raise temp of 1 kg water 1 degree C
so
311,000 = 4190 (1.50)(T-0)
T = 311,000/ [4190*1.5 ]