Chemistry

A hydrate of copper (II) sulfate with formula CuSO4.xH2O has a molar mass of 250.0 g/mol. 2.545 g of hydrate is heated and 63.85% of the residue is found after heating.
a) Determine the value of x in the formula of the compound
b) What is the molecular formula of the hydrate?

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asked by Kai
  1. mass hydrate before heat = 2.545 g
    mass hydrate after heat = 2.545 x 0.6385 = 1.625 g = mass CuSO4
    mass H2O = 2.545-1.625 = 0.9200 g
    mols H2O = 0.9200/18 = 0.0511
    mols CuSO4 = 1.625/159.6 = 0.01

    Convert to integers and round to whole numbers for find answer to b. That will give you answer to a.
    You can work this another way using the 250 g/mol in the problem and I did it another way.

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