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Math Ms.Sue
What is the Simplified form? (14x)^0y^7z. my answer is C. A.)14z/y^7 B.)14z/y67 C.)z/y^7 D.)z/y^7 Thank You.
asked by Deborah on January 9, 2013 
math
Simplify the Expressions 1) 4(3x3) + 9(x+1)= 3x21 2) 9x(5x+4)+10(x+3)= 45x26 x+3 3) n(1+ 10n)n(4n3)= 4n+6n 4) 2n(8n10)6(10n3)= 96n  10 5) 8(4x7)+3(99x)= 59x  29 6) 9(310n)3(10n+1)= 30n  3 7)
asked by Alayasia on October 25, 2010 
Math
you know that 8x = 5y you know that 3y=14z since 5 = (5/3)*3, 5y = (5/3)*(3y) so, 5y = (5/3)(3y) = (5/3)(14z) = (70/3)z now you have 5y, which is the same as 8x. You want 12x. since 12 = (3/2)*8, 12x = (3/2)*8x. 12x = (3/2)(8x) =
asked by Kevin on January 10, 2015 
Penn Foster
I am looking for the questions to these exams..all I keep getting are the darn answers...I want to compare my answers before I submitt anyone have the orginal questions? to these Anyone have the questions for the penn foster exams
asked by Jessie on March 8, 2011 
Jiskha
I typed several questions and answers regarding the subject of Geography, and suddenly, as I was waiting for a reply from Ms. Sue, it seemed as though my questions were deleted from the webpage where all of the other questions are
asked by Anonymous on October 6, 2013 
Math
I am not sure which questions I got wrong but I am not getting the link correct to the next box. The website is mathbits(dot)com/caching/holiday/H30976.html I got these answers 1.) Choice 3 2.) Choice 2 3.) a.) Choice 2 b.) 63 4.)
asked by Johnathan on January 7, 2016 
Physics net force and mass
Four boxes of various masses are placed on a friction free table. Rank these boxes according to net force by listing them in order from greatest to least. A) B) C) D) Thank You :) (the _ kg  are the boxes) =)
asked by Jill on January 31, 2012 
Physics net force and mass
Four boxes of various masses are placed on a friction free table. Rank these boxes according to net force by listing them in order from greatest to least. A) B) C) D) Thank You :) I forgot to include: Which one has the most force
asked by Jill on February 1, 2012 
science
guyz got a hard question... A net force of 10N to a 5 kg mass. bY HOW MUCH does a body accelerate.. Given: F=10N;m=5kg
asked by Loraine Ordono on December 5, 2011 
Math
My Math Problem is {4/5n + 9/2} = 49/10 8/10 45/10n = 53/10n 53/10 x 49/10 = 490/530 n= 60 am I correct
asked by Americal on October 2, 2015