2 charges of 16 microculomb and 25 microculomb are separated by a distance of 2 metre apart.If another charge of 5 microculomb is placed in the middle of the line joining the 2 charges.Then what is the net force on the 5 coloumb charge
To find the net force on the 5 microcoulomb charge, we need to determine the forces exerted on it by the other two charges.
The force between two charges can be calculated using Coulomb's law, which states that the force (F) between two charges (q1 and q2) is given by the equation:
F = k * (q1 * q2) / r^2
Where:
- F is the force between the charges
- k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
Let's calculate the forces between the 5 microcoulomb charge and each of the other charges:
Force between the 5 microcoulomb charge and the 16 microcoulomb charge:
F1 = (9 x 10^9 Nm^2/C^2) * ((5 x 10^-6 C) * (16 x 10^-6 C)) / (1m)^2
Force between the 5 microcoulomb charge and the 25 microcoulomb charge:
F2 = (9 x 10^9 Nm^2/C^2) * ((5 x 10^-6 C) * (25 x 10^-6 C)) / (1m)^2
Since the 5 microcoulomb charge is equidistant from both charges, the net force on the 5 microcoulomb charge is the vector sum of F1 and F2:
Net force on the 5 microcoulomb charge = F1 + F2
Now let's calculate the net force on the 5 microcoulomb charge.