A Spanish class has a total of
46
students. The number of females is
14
less than the number of males. How many males and how many females are in the class?
f + f + 14 = 46
2f = 32
f = 16
males=x
females=x-14
x+x-14=46
2x-14=46
you take 14 to the other side
46+14=60
2x=60
x=60/2=30
males=30
females=30-14=16
N/B:if you have not understood let me know
Let's assume the number of males in the class is x.
According to the problem, the number of females is 14 less than the number of males.
So, the number of females is (x - 14).
The total number of students in the class is 46, which means the number of males plus the number of females should equal 46.
So, we can write the equation as:
x + (x - 14) = 46
Simplifying the equation, we have:
2x - 14 = 46
Adding 14 to both sides of the equation:
2x = 46 + 14
2x = 60
Dividing both sides by 2:
x = 60/2
x = 30
Therefore, there are 30 males and (30 - 14) = 16 females in the class.
To find the number of males and females in the Spanish class, we'll use algebra.
Let's assume the number of males in the class is "x". Since the problem states that the number of females is 14 less than the number of males, we can represent the number of females as "x - 14".
We know that the total number of students in the class is 46. So, we can write the equation:
x + (x - 14) = 46
Now, let's solve this equation to find the value of x.
Combine like terms:
2x - 14 = 46
Add 14 to both sides to isolate the variable:
2x = 60
Divide both sides by 2 to solve for x:
x = 30
Now, we know that there are 30 males in the class. To find the number of females, substitute the value of x back into our earlier equation:
30 - 14 = 16
So, there are 30 males and 16 females in the Spanish class.