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Find the ratio of rate dffusion of So2 ,O2,CH4?
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Sorry it's chemistry, I have written math its my mistake.
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Find the ratio of rate diffusion of SO2,O2, CH4?
Top answer:
The answer is in a ratio of 1:2
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What ratio is used to carry out each conversion?
a.mol CH4 to grams CH4 b.L CH4(g) to mol CH4(g)(at STP) c.molecules CH4 to mol
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1 mol CH4 x (16 g CH4/1 mole CH4) = ?g CH4 L CH4 x (1 mole CH4/22.4 L) = ? moles CH4 #molecules CH4
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how much oxygen is required to convert total so2 into so3 tell me the percentage ratio of so2:o2
the reaction is so2+1/2o2=so3
Top answer:
each O2 reacts with 2SO2, so in moles, the ratio would be 2:1 in mass, convert from moles to grams.
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ratio of rate of diffusion of O2 and CH4
Top answer:
rate of diffusion is inversely proportional to masses. R02/RCH4 = sqrt (16/32)= 1/sqrt2=.707
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the reaction is CO + SO3 <=> CO2 + SO2, the rate law for this reaction is rate=k[SO3] and the mechanism is
SO3 -> SO2 + O CO + O
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To determine the slow step in the given reaction mechanism, we need to compare the rate-determining
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The equilibrium 2 SO2(g) + O2(g) 2 SO3(g) has the value K = 2.5 1010 at 500. K. Find the value of K for each of the following
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No, that isn't the way to approach it. For the reaction A + B = C + D Given that K = 25 For 2A + 2B
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1) The rate expression for the reaction 2 SO2 + O --> 2 SO3 is given by rate = k [SO2]2[O2]. The overall order of this reaction
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Are these true/false questions? If so, the answers are (1) T, (2) F, (3) F.
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calculate the densities of each of the following gases in g/L at STP:
a. F2 b. CH4 c. Ne d. SO2
Top answer:
One (1) mole of a gas occupies 22.4 L at STP. For example, F2 = 19x2=38 grams and 38/22.4 L = ??g/L
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Graham's Law predicts that the ratio of the rate of effusion of gas X to the rate of gas Y equals the square root of the
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Why didn't you show how you came up with that answer? I could have found the error.
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Doing review for an exam and I can't find how to do this problem in my notes.
2 SO2 + 2 Cl2 -----> 2 SOCl2 + O2 from a previous
Top answer:
To answer your questions, you can use the concepts of the Arrhenius equation and the principle of
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