What will happen from the following if H3C-C6H6-N2Cl is treated with Na2CO3?
a)CO2 will emit
2)NH3(g) will emit
c)N2Cl-C6H6-CH3 will be produced
d) NH2-C6H6-CH3 will be produced
We get C6H6-NH2 when Sn/conc.HCl are reacted with Nitro Benzene.This become Aniline when excess NaOH is added.
And this will become the above product if reacted with NaNO2/HCl(HNO2) at 0-5°C.
We know that when treated with Na2CO3 (aq)solution RCOOH will emit CO2.Same way will the given compound emit CO2? Or NH3 ?
To determine what will happen when H3C-C6H6-N2Cl is treated with Na2CO3, we need to analyze the different functional groups in the compound and their reactivity.
H3C-C6H6-N2Cl contains a benzene ring (C6H6) and a chloride group (Cl) attached to a nitrogen atom (N2). Na2CO3 is a basic compound commonly known as sodium carbonate.
Given the reaction conditions and reactivity patterns of the functional groups involved, we can predict the following outcomes:
1) CO2 will emit:
When Na2CO3 reacts with carboxylic acids (RCOOH), it produces carbon dioxide (CO2) gas. However, the given compound does not contain a carboxylic acid. Therefore, CO2 emission is unlikely in this reaction.
2) NH3(g) will emit:
The presence of a chloride group suggests that the compound may be an alkyl chloride. When alkyl chlorides react with a strong base like Na2CO3, they undergo a nucleophilic substitution reaction. In this case, the nitrogen atom could act as the nucleophile and replace the chlorine atom with the carbonate ion (CO3^2-). This would result in the formation of NH3 gas (ammonia). Therefore, it is possible that NH3(g) will emit.
3) N2Cl-C6H6-CH3 will be produced:
Given that the compound contains a nitrogen atom and a chlorine atom, it is possible that a substitution reaction could take place. However, the specific reaction conditions and reagents required for the formation of N2Cl-C6H6-CH3 are not provided. Therefore, it is unlikely that this specific product will be formed in this reaction.
4) NH2-C6H6-CH3 will be produced:
The given compound contains a benzene ring and a nitrogen atom. When alkylating agents like Sn/conc.HCl and excess NaOH are used, the compound NH2-C6H6-CH3, also known as aniline, can be formed. However, Na2CO3 is not the appropriate reagent for this type of reaction. Hence, it is unlikely that NH2-C6H6-CH3 will be produced in this reaction.
In conclusion, based on the given information, the most likely outcome is that NH3(g) will emit when H3C-C6H6-N2Cl is treated with Na2CO3.