The average daily minimum temperature for Pablo’s hometown can be modeled by the function f(x)=15.3sin(πx6)+44.1 , where f(x) is the temperature in °F and x is the month.
x = 0 corresponds to January.
What is the average daily minimum temperature in June?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
okay so on my previous post i knew what to do so i know that 5 is x=5 so i subtracted 3.14 from 5 plus divided it by 6 and got 2.306 and on my calculator i hit sin and got 0.741 now im a bit confused
15.3 sin(pi*5*6) + 44.1
no way
I think maybe you mean
15.3 sin (pi x/6)
but I do not believe that either because it should be colder in January than in July when you have sin (pi) which is also 0. This has maximum temp in April, no way
To find the average daily minimum temperature in June, you need to substitute x=6 into the equation f(x)=15.3sin(πx/6)+44.1.
Let's break down the calculation step by step:
1. Substitute x=6 into the equation:
f(6) = 15.3sin(π(6)/6)+44.1
2. Simplify the expression inside the sine function:
f(6) = 15.3sin(π)+44.1
3. Since sin(π) equals 0, we can simplify further:
f(6) = 15.3 * 0 + 44.1
4. Multiply 15.3 by 0:
f(6) = 0 + 44.1
Now, the answer to the question is the value of f(6), which equals 44.1.
Therefore, the average daily minimum temperature in June is 44.1°F.
what you need to do is recognize the special angles with known trig values.
π/6 is one of those angles.
sin(5π/6) = sin(π/6) = 1/2
the real question is: why did you calculate (5-pi)/6 instead of just doing 5pi/6 ?
If your function is
f(x)=15.3sin(πx6)+44.1
propagating your typo for the 5th time or so, why did you not calculate (π*5*6)? It does not say sin (π-x)/6