Collin has a fair coin and a fair 10-sided number cube labeled 1-10. He performs this experiment 150 times to determine the experimental probability that heads is tossed and the number 2 is rolled. Which of the following is most likely to be the experimental probability that Collin determined?

I think heads is 1/2 and i think 2 is 1/10. if you multiply them you get 1/20...times 150=7 1/2.
how do i get the correct answer? because 7 1/2 is wrong.

since you did not list the choices, I can't tell "which of the following is most likely to be the experimental probability".

The probability of the event you stated is (1/2)(1/10) = 1/20
which you had

the choices are a) 3/7 b) 1/3 c) 3/40 d) 2/37

Again, without the choices, we cannot know which one is the most likely.

However, since we are talking about experimental probability, and that we cannot have an outcome of 7.5 times out of 150. Therefore the most likely result could be 7/150 or 8/150, whatever their decimal equivalents are.

To find the experimental probability of both events occurring (tossing heads and rolling a 2), you need to divide the number of successful outcomes by the total number of trials.

In this case, Collin performed the experiment 150 times. The probability of getting heads on a fair coin is 1/2, and the probability of rolling a 2 on a fair 10-sided number cube is 1/10.

To calculate the number of successful outcomes for both events occurring, you multiply the probabilities:
(1/2) * (1/10) = 1/20

To calculate the experimental probability, you multiply the probability by the number of trials:
(1/20) * 150 = 7.5

So, based on your calculations, the experimental probability is indeed 7.5. However, the result should be expressed as a decimal, not as a mixed number (7 1/2). Therefore, the correct answer would be 7.5, rather than 7 1/2.